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Oxidation and reduction in electrolysis - Higher

Half equations

A is used to represent the reaction that happens at an during . It shows what happens when gain or lose . In half equations:

  • electrons are shown as e-
  • the numbers of of each must be the same on both sides
  • the total on each side must be the same (usually zero)

Cathode reactions

Positively charged ions gain electrons at the . These are half equations for some reactions at the cathode:

Na+ + e- → Na

Pb2+ + 2e- → Pb

2H+ + 2e- → H2

Example

Balance the half equation for the formation of aluminium during electrolysis: Al3+ + e- → Al.

The balanced half equation is: Al3+ + 3e- → Al (because three negatively charged electrons are needed to balance the three positive charges on the aluminium ion).

Question

Write a balanced half equation for the formation of calcium from a calcium ion, Ca2+.

Half equations for anode reactions

Negatively charged ions lose electrons at the . For example

2Cl- → Cl2 + 2e-

2O2- → O2 + 4e-

Example

Write a balanced half equation for the formation of oxygen from hydroxide ions.

4OH- → 2H2O + O2 + 4e-

Question

Write a balanced half equation for the formation of bromine, Br2, from bromide ions, Br-.

Oxidation and reduction

and can be described in terms of electrons:

  • oxidation is the loss of electrons
  • reduction is the gain of electrons

This means that:

  • reduction happens at the cathode
  • oxidation happens at the anode

This can be seen by looking at the half equations above.

It helps to remember OIL RIG - Oxidation Is Loss of electrons, Reduction Is Gain of electrons.

Learn more on redox reactions in this podcast.