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Relative atomic mass

Different have different masses. Atoms have such a small it is more convenient to know their masses compared to each other. Carbon is taken as the standard atom and has a relative atomic mass (Ar) of 12.

  • Atoms with an Ar of less than this have a smaller mass than a carbon atom.
  • Atoms with an Ar that is more than this have a larger mass than a carbon atom.

Ar values of elements

The table shows some Ar values:

ElementRelative atomic mass
Hydrogen, H1
Carbon, C12
Oxygen, O16
Magnesium, Mg24
Chlorine, Cl35.5
ElementHydrogen, H
Relative atomic mass1
ElementCarbon, C
Relative atomic mass12
ElementOxygen, O
Relative atomic mass16
ElementMagnesium, Mg
Relative atomic mass24
ElementChlorine, Cl
Relative atomic mass35.5

These values tell you that a magnesium atom has twice the mass of a carbon atom, and 24 times more mass than a hydrogen atom. They also tell you that hydrogen atoms have 12 times less mass than a carbon atom. The Ar values also allow you to work out that three oxygen atoms have the same mass as two magnesium atoms.

ǰԱ’s Ar of 35.5 is an average of the masses of the different of chlorine.

Calculating relative atomic mass from isotopic abundance [Higher tier only]

The relative atomic mass of an element is a weighted average of the masses of the atoms of the isotopes – because if there is much more of one isotope then that will influence the average mass much more than the less abundant isotope will.

For example, chlorine has two isotopes: 35Cl and 37Cl. But the relative atomic mass of chlorine is not 36. In any sample of chlorine, 75 per cent of the atoms are 35Cl and the remaining 25 per cent are 37Cl.

The relative atomic mass is worked out using the following formula, illustrated for two isotopes, where the abundances are given in percentage values.

\(A_{r} = \frac{(mass~1 \times abundance~1) + (mass~ 2 \times abundance~2) + \ldots}{100}\)

For example, using chlorine:

\(A_{r} = \frac{(35 \times 75) + (37 \times 25)}{100}\)

\(A_{r} = \frac{(2625) + (925)}{100}\)

\(A_{r} = \frac{3550}{100}\)

\(A_{r} = 35.5\)